Programming Fundamentals Questions
Language-agnostic building blocks of writing code: variables, primitive and composite data types, scope and lifetime, functions and callbacks, control flow, and expressions versus statements. Covers the mental model a candidate needs before any language-specific or algorithmic depth. The baseline literacy layer of a technical screen.
What is a closure, and what does it capture from its enclosing scope? Explain, with a small code example, how a closure or a callback holding a reference can keep an object alive longer than expected (for example through a reference cycle), and describe a practical strategy to avoid or detect that kind of memory retention in a long-running process.
Sample Answer
Direct answer
A closure is a function bundled together with references to the variables from its enclosing scope that it uses, captured by reference (not by value), so it keeps seeing the CURRENT value of those variables even after the enclosing function has returned. That captured reference can create a reference cycle, which is why a closure or callback can keep an object alive longer than you expect.
Structured elaboration
- What gets captured: a closure captures the variable itself (technically, the enclosing scope's cell), not a snapshot of its value at creation time. Two closures created from the same enclosing call share independent state; two closures created from the SAME variable in a loop share the same captured cell, which is the classic 'all my callbacks report the same, final loop value' bug.
- Why closures can leak memory: a closure keeps a live reference to everything it captures for as long as the closure itself is reachable. If you then store that closure back onto an object it captured (a callback registered on the very object it was built from), you've created object -> closure -> object, a reference cycle.
- Why reference counting alone can't free a cycle: CPython's primary memory management is reference counting, an object is freed the instant its reference count hits zero. In a cycle, each object holds a reference to the other, so neither one's count ever reaches zero on its own, even after nothing OUTSIDE the cycle references either of them. This is precisely why CPython also runs a separate cyclic garbage collector (
gcmodule) that periodically looks for groups of objects that reference each other but are unreachable from anywhere else, and frees them as a group. - Mitigation strategies: avoid storing a closure back onto the object it captures when you can restructure to avoid it; use
weakreffor a back-reference that shouldn't keep the target alive (a common pattern for observer/callback registries); or simply trust the cyclic collector for genuinely short-lived cycles and only investigate further if profiling shows real, growing retention in a long-running process.
Worked example
class Node:
def __init__(self, name):
self.name = name
self.on_event = None
def wire(node):
def handler(): # closure: captures `node`
return f"{node.name} handled"
node.on_event = handler # node -> handler -> node : a cycle
return handler
Verified by running it with gc.disable() and a weakref to the node: after del n (dropping the only external reference), the node is STILL alive (ref() is not None is True) because the cycle keeps both objects' reference counts above zero. Re-enabling the collector and calling gc.collect() reclaims it (ref() is None becomes True immediately after), confirming the cyclic collector, not reference counting, is what actually frees this pattern.
Trade-offs & pitfalls
In a long-running service, this usually shows up as slow, steady memory growth rather than an obvious crash, because the cyclic collector DOES eventually run and free most cycles; the real danger is cycles involving objects with a __del__ method (historically these were UNCOLLECTABLE by the cyclic GC before Python 3.4, and even post-3.4 they add real collection overhead) or large cycles that make each collection pass more expensive as the live object graph grows. The fix is rarely 'stop using closures', it's to be deliberate about back-references specifically, using weakref where a callback registry would otherwise hold the only thing keeping a large object graph alive.
Explain the difference between stack and heap memory: what gets allocated where, how variable lifetime differs between the two, and what common pitfalls arise (for example a dangling reference in an unmanaged language, or an object staying reachable longer than intended in a managed one).
Sample Answer
Direct answer
The stack holds each function call's local variables and control-flow bookkeeping in a strict last-in-first-out region that's automatically reclaimed the instant a function returns; the heap holds data whose lifetime isn't tied to any single function call, and it's reclaimed either manually (unmanaged languages) or by a garbage collector (managed languages).
Structured elaboration
- What lives where: a local primitive variable, or in some languages a fixed-size value type, is allocated on the stack as part of the current function's frame. Anything created with an explicit allocation (
newin Java/C++, any Python object, since CPython objects are always heap-allocated even for anint) lives on the heap; the stack only holds a reference/pointer to it. - Variable lifetime: a stack frame's contents die the moment that function returns, this is why you can't return a pointer to a local stack variable in C and expect it to still be valid. Heap objects live until nothing references them anymore, tracked either by the programmer (manual
free/delete), reference counting, or a tracing garbage collector. - Managed vs unmanaged: in C/C++, forgetting to free heap memory is a leak, and freeing it twice or using it after freeing ("use-after-free") is undefined behavior, a classic source of crashes and security bugs. In managed languages like Java or Python, the heap is reclaimed automatically, which removes that class of bug but introduces its own failure mode: an object that's still reachable (through a lingering reference you forgot about) never gets collected even though you're logically done with it, this looks exactly like a leak from the outside even though nothing is 'wrong' with the GC.
- Common pitfalls: dangling references (using a pointer after its target was freed) and double-free in unmanaged languages; unintentional retention (a cache, a global list, or a closure holding a reference longer than intended) in managed languages, which is the managed-language equivalent of a leak.
Worked example
A function def compute(x): result = x * 2; return result allocates result in its stack frame; that frame disappears the instant compute returns. If instead the function does def compute(x): return [x, x*2], the list object itself lives on the heap, only the reference to it lived momentarily in the stack frame, and the list survives the function return because the caller now holds a reference to it. This is exactly why returning a local list is safe in Python (you're returning a heap reference) while returning a pointer to a local stack array in C is not (you're returning a pointer to memory that's about to be reused by the next function call).
Trade-offs & pitfalls
Stack allocation is fast (just moving a pointer) and has zero collection cost; heap allocation is more flexible (variable size, unpredictable lifetime) but costs more per allocation and, in a managed language, imposes collection work (pause time, throughput cost) somewhere down the line. This is a large part of why some languages let you opt certain data onto the stack explicitly (value types, structs) when you know its lifetime is scoped to the current call, to avoid heap/GC overhead for short-lived data.
Explain what happens mechanically when you write a try/except/finally block (or the equivalent in your language): what runs, in what order, when no exception occurs, when one is raised and caught, and when one is raised and NOT caught. Then walk through handling a file-I/O error inside a function that opens a file, using the construct to guarantee the file is always closed even when an error occurs.
Sample Answer
Direct answer
try marks a block whose exceptions you want to intercept; except runs only if a matching exception is raised inside the try; finally always runs, whether or not an exception occurred and whether or not it was caught, and it runs even if the exception propagates past this block entirely.
Structured elaboration
- No exception: the
tryblock runs to completion, everyexceptclause is skipped, thenfinallyruns. Nothing unusual happens. - Exception raised and caught: execution jumps out of the
tryblock the instant the exception is raised (any code after the raising line intrydoes NOT run), the first matchingexceptclause runs, thenfinallyruns. - Exception raised and NOT caught (no
exceptclause matches its type): the matching-exceptsearch fails,finallystill runs (this is the part people get wrong:finallyis not conditional on being caught), and only afterfinallycompletes does the exception continue propagating up to the caller. - The consequence that matters in practice:
finallyis the correct place for resource cleanup that must happen unconditionally, closing a file handle, releasing a lock, rolling back a partially-started operation, precisely because it is the one block guaranteed to run on every exit path from thetry.
Worked example
def no_exception():
order = []
try:
order.append('try')
except ValueError:
order.append('except')
finally:
order.append('finally')
return order
def caught_exception():
order = []
try:
order.append('try')
raise ValueError('boom')
except ValueError:
order.append('except')
finally:
order.append('finally')
return order
Running both (verified): no_exception() returns ['try', 'finally'] (the except clause never runs), caught_exception() returns ['try', 'except', 'finally']. A third case with a TypeError raised where only ValueError is caught confirms finally still runs before the TypeError propagates out to the caller, exactly as described above.
For the file-I/O case, opening a file and guaranteeing it closes even on a mid-read failure:
def read_lines(path):
f = open(path, 'r')
try:
return f.readlines()
finally:
f.close() # runs whether readlines() succeeds, raises, or the caller's except re-raises
This is exactly what a with open(path) as f: block (or Java's try-with-resources) does under the hood, they are sugar over a try/finally that closes the resource. In this pattern, whether to re-raise the error after logging it or return a sentinel value to the caller depends on whether the caller can meaningfully continue: propagate (let the exception continue, possibly after logging) when the caller cannot proceed without the data; return a sentinel only when the caller has a genuine, documented fallback.
Trade-offs & pitfalls
The most common mechanical mistake is assuming finally only runs when an exception was caught, when in fact it runs on every exit from try (normal completion, caught exception, uncaught exception, even a return inside the try block). The second most common mistake is putting cleanup code after the try/except instead of in finally, which silently skips cleanup on any path that doesn't hit that exact line, exactly the bug that finally exists to prevent.
What is a pure function? Contrast it with a function that has side effects, and give an example of each. Why does purity matter for testability and for safe parallel execution?
Sample Answer
Direct answer
A pure function's output depends only on its inputs, and calling it produces no observable effect outside its own return value, no mutation of external state, no I/O, no reliance on anything that could change between calls. A function with side effects does at least one of those things: it might mutate a variable outside its own scope, write to a file, or return a different result for the same input depending on some external state.
Structured elaboration
- Same input, same output, always: this is the defining property.
math.sqrt(4)is pure, it returns2.0every single time. A function that reads the current time, a global counter, or a mutable default argument that accumulates across calls is not pure, its output can differ across calls even with identical arguments. - No observable effects outside the return value: a pure function doesn't print, doesn't write to a database, doesn't mutate an object passed into it, doesn't increment a counter defined outside itself. If you could delete every call to it (assuming nothing used the return value) and the rest of the program's behavior would be unchanged, that's a strong sign of purity; if deleting a call changes behavior beyond 'the return value is no longer available', something impure happened inside it.
- Why purity matters for testing: a pure function needs no setup beyond its arguments and no teardown, you call it, you assert on the return value, done. An impure function's test has to also arrange whatever external state it reads, and verify whatever external state it mutates, which multiplies both the setup complexity and the number of ways the test can be wrong or flaky.
- Why purity matters for parallel execution: if a function only reads its inputs and produces a return value, calling it concurrently from multiple threads for different inputs is automatically safe, there's no shared mutable state for two calls to race on. An impure function that mutates shared state needs explicit synchronization (locks) to be safe under concurrency, or it will produce wrong results or crashes under load in a way that's notoriously hard to reproduce.
Worked example
def add_tax_pure(price, rate):
return price * (1 + rate) # no side effects
total_calls = {"count": 0}
def add_tax_impure(price, rate):
total_calls["count"] += 1 # side effect: mutates external state
return price * (1 + rate)
Verified: add_tax_pure(100, 0.08) returns 108.0 every time it's called, and calling it twice does not change anything else observable in the program. add_tax_impure(100, 0.08) returns the same 108.0, but after two calls total_calls["count"] has become 2, a change visible to any OTHER code that also reads total_calls, which is exactly the kind of hidden coupling purity avoids: two unrelated pieces of code that both happen to call add_tax_impure now silently affect each other's view of total_calls.
Trade-offs & pitfalls
Purity isn't free, and most real programs need SOME side effects (writing output, updating a database) somewhere; the useful discipline is not 'eliminate all side effects everywhere' but 'push side effects to the edges of the system and keep the core computation (the actual business logic, the actual data transformation) pure', so the large majority of the code gets the testing and concurrency benefits, and the necessarily-impure parts are small, isolated, and easy to reason about individually.
Explain mutability versus immutability: what makes an object immutable, and what are the performance and safety trade-offs? Give examples in one or two languages of your choice, discuss how immutability helps with concurrent/multithreaded correctness, and describe when immutability itself can become a performance problem.
Sample Answer
Direct answer
An immutable object's state can never change after construction, any operation that looks like a modification actually produces a new object; a mutable object's state can be changed in place through the same reference. The trade-off is safety and reasoning simplicity (immutable) versus avoided copying and lower memory churn (mutable).
Structured elaboration
- What immutability buys you: once you hold a reference to an immutable object, nobody else holding a different reference to the SAME object can surprise you by changing it out from under you. This matters most where a value is shared: as a dict/set key (see the containers discussion), as a default function argument, and across threads.
- Why it helps concurrency specifically: a data race requires at least one thread to write while another reads (or writes) the same memory. If the object literally cannot be written to after construction, that half of the race is structurally impossible, so immutable data can be freely shared across threads with zero synchronization (no locks needed) for reads. This is a much stronger guarantee than 'we were careful with locking'.
- What it costs: every 'modification' allocates a new object and (for anything nontrivial) copies the parts that didn't logically change. For a small string this is free; for a large data structure updated in a tight loop, allocating a full new copy per update can dominate runtime and memory traffic, this is the performance problem immutability can become.
- Java's concrete example:
Stringis immutable, every apparent concatenation makes a newStringobject; repeatedly concatenating in a loop is a classic O(n^2) performance trap for exactly this reason, which is whyStringBuilder(a mutable, purpose-built accumulator) exists as the escape hatch. Python'stuplevslistis the same shape:tuplegives you the sharing-safety and hashability of immutability,listgives you cheap in-place growth when you know you own the only reference.
Worked example
name = "engineer"
upper_name = name.upper() # returns a NEW string; name itself is untouched
assert name == "engineer"
assert upper_name == "ENGINEER"
nums = [1, 2, 3]
nums.append(4) # mutates the SAME list object in place
assert nums == [1, 2, 3, 4]
(both assertions verified). name.upper() cannot change name because Python strings are immutable, there is no operation that mutates a str in place; nums.append(4) changes the exact object nums refers to, so any other variable that also referenced that list would see the appended 4 too, that aliasing behavior is the concrete risk mutable shared state introduces.
Trade-offs & pitfalls
The practical decision is rarely 'immutability is always better', it's 'default to immutable for anything shared or used as a key, and reach for mutable structures deliberately, in the narrow scope where you know you own the only reference and the update pattern is hot enough that copy-on-write would actually cost something measurable'. Treating one choice as universally correct, in either direction, is the mistake.
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